Quote:
Originally posted by Hugamari
Ew @ whatever the **** it is Clarkson posted. Go to the Lounge because some people there love any chance they get to feel superior over others by solving obscure brain teasers.
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The accuracy
I might have to thread it
Quote:
Originally posted by 8thPrince
Two odds will always make an even. So divide the sum of the numbers by the time it takes you to withdraw from this class and you should have your answer.
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Too late to withdraw now
Quote:
Originally posted by Tymps.
"each pile" like only one has to add up to an odd number or all three have to?
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All three.
Quote:
Originally posted by Vulnicura
wait my maths degree has been building to this moment
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Then solve it fat.
Quote:
Originally posted by Tymps.
Okay if every pile has to be odd, then one pile must have three odd and the other two must have one odd each.
I literally did some random ass math (I'm really bad at applying things I guess!) and got 1/63 if it needs to be every pile that's odd. It doesn't make sense for it to be, like, 50%, right?!?!
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Yeah, I don't think the 50% is right, it doesn't make any sense to me.
Quote:
Originally posted by swiftie13
I did not test out of all my math classes the second I began college to be exposed to this kind of torture on here. K thnx
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Sorry b.
The funny thing is, I'm not taking any math this semester. That's a Logic question.
)
