These are all P&C questions (A-level standard). But some can be solved by basic math!

QUESTION 5: (got this from a book since yall are so good) A group of 12 people consists of 6 married couples. The group stands in a circle.
(a) Find the number of possible arrangements
(b) Find the number of different possible arrangements if men and women alternate
(c) Find the number of different possible arrangements if each man stands next to his wife and the men and women alternate

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QUESTION 4: (got this from a book since yall are so good) In how many ways can 5 books be distributed among 10 people, if
(a) the 5 books are distinct and no one gets more than one copy
(b) the 5 books are distinct and each person can get any number of books
(c) The 5 books are identical and no one gets more than one copy
(d) the 5 books are identical and each person can get any number of books

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QUESTION 3: How many 3 figure numbers have two and only two consecutive figures identical? (simple one first. thinking of a hard qn)

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QUESTION 2:There are 100 people in a party. If everyone were to shake hands with each other only once, how many handshakes will the be in total? (DONT POST THE FORMULA! JUST THE ANS )

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QUESTION 1:How many ways can you get out of this maze (from IN to OUT) if you can only move UP and RIGHT. This means that you cannot move backwards (DOWN / LEFT).

Basically, move from the bottom left corner of the maze to the top right corner by moving along the lines!

(There is an example below if you do not understand what I mean)





EXAMPLE:

You can only move UPWARDS AND TOWARDS THE RIGHT along the lines


First to solve
QN1: aloirt
QN2: Kingfisher
QN3: Optimus
QN4(c): Middle of Selena
QN4(a): Optimus
QN4(b): Middle of Selena
QN5(a): Optimus

62?


EDIT:

The answer

just use this formula, m and n are the numbers of rows and columns.

[(m+n)!] / [m!×n!]

= 12! / (8! * 4!) = 495

Originally posted by jacklovesyou1 26?

Originally posted by aloirt 62?

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Originally posted by aloirt 62? EDIT: The answer just use this formula, m and n are the numbers of rows and columns. [(m+n)!] / [m!×n!] = 12! / (8! * 4!) = 495

Originally posted by aloirt 62? EDIT: The answer just use this formula, m and n are the numbers of rows and columns. [(m+n)!] / [m!×n!] = 12! / (8! * 4!) = 495

Originally posted by aloirt 62? EDIT: The answer just use this formula, m and n are the numbers of rows and columns. [(m+n)!] / [m!×n!] = 12! / (8! * 4!) = 495

Originally posted by getback my math game is weak what does ! stand for? I learnt about it before but after 4 years since high school, I totally forgot

Originally posted by Tymps. Hunty I posted a PEMDAS question on here once and people couldn't solve it, I don't know what you're expecting

Originally posted by Kingfisher that one's 4950, right?

Originally posted by Kingfisher that one's 4950, right?

Originally posted by sgcat 495 for qn1