[BabyCantYouSee]

Y'all are speaking gibberish to me.

This is probably the last year I'm taking any sciences. Thank God. I only truly like Biology, but I couldn't even take that this year since it conflicted with my math course. I barely passed my Physics quiz two days ago. The two sciences are going to weigh my average DOWN.

[conseeded]

Originally posted by BabyCantYouSee

Y'all are speaking gibberish to me.

This is probably the last year I'm taking any sciences. Thank God. I only truly like Biology, but I couldn't even take that this year since it conflicted with my math course. I barely passed my Physics quiz two days ago. The two sciences are going to weigh my average DOWN.

I'm like that with Chemistry. That **** does NOT make sense to me. Still thankful I don't have to take any Physics classes either.

Biology, Psych, and Sociology come easy to me though.

[RatedG²]

Can anyone help me with Calculus homework? I said I was good at it but this intergral **** got me confused

[BabyCantYouSee]

Originally posted by RatedG²

Can anyone help me with Calculus homework? I said I was good at it but this intergral **** got me confused

Didn't start calculus yet, sorry. I would've helped if I could.

You should try www.khanacademy.com They give such thorough explanations, I've learned so much from that site.

--

@conseeded, I LOVE biology. I was so pissed that I couldn't take it this year. I'm taking AP Sociology this year as well. The psych class got cancelled, I was supposed to take that too.

[chilicheese01]

Find the vertical asymptote, if any, of the function:

f(x) = ((4) / (x - 2)^3)

[GaGaFan]

Originally posted by chilicheese01

Find the vertical asymptote, if any, of the function:

f(x) = ((4) / (x - 2)^3)

The vertical asymptote is the part of the graph where the bottom is equal to zero.

[RatedG²]

Originally posted by GaGaFan

The vertical asymptote is the part of the graph where the bottom is equal to zero.

This.

So the vertical asymptote should be at x=2

[LoudR]

Anyone good with Classical Studies? Something literature related..

[chilicheese01]

I know this is really basic, but somebody clarify.

lim
x->1+ of (2+x)/(1-x)

Would I just plug in 1 for the values of x and that would be my limit? Or is there more to it? My math teacher this year is terrible.

[RatedG²]

Originally posted by chilicheese01

I know this is really basic, but somebody clarify.

lim
x->1+ of (2+x)/(1-x)

Would I just plug in 1 for the values of x and that would be my limit? Or is there more to it? My math teacher this year is terrible.

Sorry I'm on mobile so I can't help you much but if you plug in 1, you see that the denominator equals 0 and that can't be possible. So you have to manipulate the equation to make sure the denominator ≠ 0. I would do it myself but like I said I'm on mobile. I'm sure another could help you

[RatedG²]

Originally posted by LoudR

Anyone good with Classical Studies? Something literature related..

Try coolest person12

[highwind44029]

OMG academics. I'mma perch in this thread because I can't seem to recall any of the **** you guys talk about, but I feel like I need to remember so I don't get Alzheimer's.

[Auburn]

I feel like this could become my favourite thread.

[posh]

Y'all doing this calculus stuff while I struggle to remember 2 negatives make a positive.

[stbernarddoggy]

Originally posted by chilicheese01

I know this is really basic, but somebody clarify.

lim
x->1+ of (2+x)/(1-x)

Would I just plug in 1 for the values of x and that would be my limit? Or is there more to it? My math teacher this year is terrible.

This means what is the limit as x "approaches" 1 from the right side. So easiest way would be plug in 1.001 (or any number slightly bigger than 1) with a calculator and get an answer, or pick a number (if you don't have a calculator) that is slightly bigger than 1. (Let's use 1.001 for simplicity sake)

so you plug 1.001 in for x and you get

( 2 + 1.001) / (1 - 1.001) = (3.001)/(-0.001) = - infinity.

Since any positive number divided by any small negative number is always negative infinity.

[naomi24]

Originally posted by posh

Y'all doing this calculus stuff while I struggle to remember 2 negatives make a positive.

Luckily I'm blessed with some math genes...although its been a long time since i did cal1 or cal 2. Integral, derivatives and limits used to be my life

[coolcristobal]

Any of y'all read The Great Expectations and Beowulf?

[KB.]

Bitch..... Like this problem should be so easy to me, but my mind is going BLANK.

Acceptance Sampling: With one method of the procedure called acceptance sampling, a sample of items is randomly selected without replacement, and the entire batch is rejected if there is at least one defect. The Newport Gauge Company has just manufactured a batch of aircraft altimeters, and 3% are defective.

a) If the batch contains 400 altimeters and two of them are selected without replacement and tested, what is the probability that the entire batch will be rejected?

b) If the batch contains 4000 altimeters and 100 of them are selected without replacement and tested, what is the probability that the entire batch will be rejected?


So I was trying to do it as a complement probability problem. so if p=.03 for defective tires then the probability of a good tire is .97 percent and the P( of getting all non defective tires) would be .97^100= 0.0475. So the probability of getting a defective tire and the entire batch being rejected is 1-0.0475= 0.952. I don't think I'm doing them right. Someone please help me.

Edit: Nevermind! I'm ashamed I even asked after finally figuring it out.

[RatedG²]

KB are you gonna be up in a few hours? I'm getting some work done now but I have calculus homework to ask , it's so damn difficult for me

[Julián]

Originally posted by RatedG²

KB are you gonna be up in a few hours? I'm getting some work done now but I have calculus homework to ask , it's so damn difficult for me

MAYBE I could help, I'm not too good but try me