Discussion: Homework Help Thread - Finals Season! - Page 30

KB.

Quote:

Originally posted by w.h.o

Help?

Based off of that it seems that the gene is only expressed in males so you could assume that it's on the Y-Chromosome.

w.h.o

Quote:

Originally posted by KB.

Based off of that it seems that the gene is only expressed in males so you could assume that it's on the Y-Chromosome.

If it was y-linked, wouldn't #5 be affected though?

KB.

Quote:

Originally posted by ilovemusic432

I'm in college. I have to do a 20 page essay, due at the end of the month. A thesis to be exact

I've never done one before though, it's always been either a regular essay or a research paper that i've done in college. The topic I chose has to do with Photography

- Talking about how much this concept of photography has changed throughout the years (Digital vs. traditional photography)

- How much this change has had an impact on society throughout the yearse, and also on this day in age.

- Maybe talking about this idea of photography and how some people may not see it as a legit type of "art form" (some may say that when you paint a picture, a lot of concepts and ideas are put into it beforehand, but when you take a picture you just point, shoot, and be done with it)

Those are two of the points, I'm just not sure how to start the thesis off. A post here or PM would be awesome

Well as with any paper you're always going to start out with a introduction. Use it to draw your audience in and make them want to read the rest of your paper. You're introducing your topic, why it's important, stating clear arguments, outlining the structure of your paper, and most importantly you're stating your thesis. Your thesis should be straight to the point about what exactly you're trying to accomplish with your body of work.

BabyCantYouSee

How much chromium, nickel, and iron would you need to make a 500 kg batch of 18/8 stainless steel, which is steel made with 18% (m/m) chromium and 8% (m/m) nickel in iron?

The rubbing alcohol that is sold in pharmacies is usually a 70% (v/v) aqueous solution of isopropyl alcohol. What volume of isopropyl alcohol is present in a 500mL bottle of this solution?

Can you guys help me with these 2 questions please? And can you explain to me how and why you did what you did?

KB.

Quote:

Originally posted by w.h.o

If it was y-linked, wouldn't #5 be affected though?

Now that I think about it... yes. So more than likely it's X linked and it isn't expressed in females because they have another X chromosome to compensate for the mutated 1

w.h.o

Quote:

Originally posted by KB.

Now that I think about it... yes. So more than likely it's X linked and it isn't expressed in females because they have another X chromosome to compensate for the mutated 1

And it could also technically be autosomal, right? I selected E for that one because two answers were plausible. Do you know anything about LOD scores? My roommate already took this class and he has no idea

KB.

Quote:

Originally posted by BabyCantYouSee

How much chromium, nickel, and iron would you need to make a 500 kg batch of 18/8 stainless steel, which is steel made with 18% (m/m) chromium and 8% (m/m) nickel in iron?

The rubbing alcohol that is sold in pharmacies is usually a 70% (v/v) aqueous solution of isopropyl alcohol. What volume of isopropyl alcohol is present in a 500mL bottle of this solution?

Can you guys help me with these 2 questions please? And can you explain to me how and why you did what you did?

For the first one, you want to make a 500 kg compound containing:

18% Chromium
8% Nickel
The remaining is going to be Iron which is 100-(18+8)=74%

So to get the amounts you would use the formula for percent (m/m) which is mass of percent (m/m) =mass of solute/mass of solution X 100.

Reaarange this formula algebraically to solve for mass of solute. That leaves this formula:

mass of solute = (percent (m/m) X mass of solution)/ 100%

KB.

Quote:

Originally posted by KB.

For the first one, you want to make a 500 kg compound containing:

18% Chromium
8% Nickel
The remaining is going to be Iron which is 100-(18+8)=74%

So to get the amounts you would use the formula for percent (m/m) which is mass of percent (m/m) =mass of solute/mass of solution X 100.

Reaarange this formula algebraically to solve for mass of solute. That leaves this formula:

mass of solute = (percent (m/m) X mass of solution)/ 100%

So....

Mass of Chromium= (18% X 500 kg)/100%= 90 kg

Mass of Nickel= (8% X 500 kg)/100%= 40 kg

Mass of Iron= (74% X 500 kg)/100%= 370 kg

BabyCantYouSee

Quote:

Originally posted by KB.

For the first one, you want to make a 500 kg compound containing:

18% Chromium
8% Nickel
The remaining is going to be Iron which is 100-(18+8)=74%

So to get the amounts you would use the formula for percent (m/m) which is mass of percent (m/m) =mass of solute/mass of solution X 100.

Reaarange this formula algebraically to solve for mass of solute. That leaves this formula:

mass of solute = (percent (m/m) X mass of solution)/ 100%

Ohhh ok. I get it. Just a few questions though. How can I tell the difference between the solute and the solution? Also, the original formula is C(m/m)= Msolute/Msolutionx100%

I plug in all the info I have, and for my missing info (which in this case is the mass), I substitute it then solve right? And I still don't get why you divide by 100% and not multiply it by 100%.

KB.

Quote:

Originally posted by w.h.o

And it could also technically be autosomal, right? I selected E for that one because two answers were plausible. Do you know anything about LOD scores? My roommate already took this class and he has no idea

I took Genetics, but we didn't cover LOD scores.

KB.

Quote:

Originally posted by BabyCantYouSee

Ohhh ok. I get it. Just a few questions though. How can I tell the difference between the solute and the solution? Also, the original formula is C(m/m)= Msolute/Msolutionx100%

I plug in all the info I have, and for my missing info (which in this case is the mass), I substitute it then solve right? And I still don't get why you divide by 100% and not multiply it by 100%.

The solution is what's being created. The solute is what you put in.

C(m/m)=Msolute/Msolutionx100%

C(m/m) X MSolution= Msolute X 100%

(C(m/m) X MSolution)/100%= Msolute

Haunter

KB, helping one kid at a time.

One kind of humanitarian.

BabyCantYouSee

Quote:

Originally posted by KB.

The solution is what's being created. The solute is what you put in.

C(m/m)=Msolute/Msolutionx100%

C(m/m) X MSolution= Msolute X 100%

(C(m/m) X MSolution)/100%= Msolute

THANK YOU KB. I LOVE 4EVER AND EVER REAL TALKS MY SISTER.

But wouldn't u have to divide by 100 if u want to find the solution as well? Not only for the solute?

KB.

Quote:

Originally posted by borntodiethisway

KB, helping one kid at a time.

One kind of humanitarian.

The struggle

KB.

Quote:

Originally posted by BabyCantYouSee

THANK YOU KB. I LOVE 4EVER AND EVER REAL TALKS MY SISTER.

But wouldn't u have to divide by 100 if u want to find the solution as well? Not only for the solute?

I'm confused what you are asking

If you're talking about the second problem. You solve it the same way as the first and the answer is 350 mL.

BabyCantYouSee

Quote:

Originally posted by borntodiethisway

KB, helping one kid at a time.

One kind of humanitarian.

LOL Ikr?

KB taking Monte's place I see.

I miss Monte btw.

BabyCantYouSee

Quote:

Originally posted by KB.

I'm confused what you are asking

If you're talking about the second problem. You solve it the same way as the first and the answer is 350 mL.

To find M solute, you'd do MSolution x percentage / 100 = Msolute

To find M Solution, you'd do M Solute x percentage/ 100 = Msolution

is that correct?

BudBud

any one doing college/uni level accounting ?
the struggle is real

BabyCantYouSee

Quote:

Originally posted by BudBud

any one doing college/uni level accounting ?
the struggle is real

I'm in HS but I know a lot about accounting since I take it and also learn from my uncle who's a chartered accountant. I can try helping?

KB.

Quote:

Originally posted by BabyCantYouSee

To find M solute, you'd do MSolution x percentage / 100 = Msolute

To find M Solution, you'd do M Solute x percentage/ 100 = Msolution

is that correct?

C(m/m)= Msolute/Msolution X 100%
C(m/m) X Msolution= Msolute X 100%
Msolution=(MsoluteX100%)/C(m/m)